A dictionary is like a list, but more general. In a list, the index positions have to be integers; in a dictionary, the indices can be (almost) any type.
>>> x = {} #This is False
>>> print(x)
{}
You can think of a dictionary as a mapping between a set of indices (which are called keys) and a set of values.
>>> x['one'] = 'apple'
>>> print(x)
{'one': 'apple'}
In general, the order of items in a dictionary is unpredictable.
>>> x = {'one':'apple','two':'banana','three':'orange'}
>>> print(x)
{'one':'apple','three':'orange','two':'banana'}
>>> print(x['two'])
'banana'
>>> len(x)
3
Adding New Key-Value Pairs
>>> alien = {}
>>> alien['color'] = 'green'
>>> alien['point'] = 5
>>> print(alien)
{'color': 'green', 'points': 5}
To create a dictionary, start with an empty one, and add the key-value pairs. The keys should be immutable and there is no repeated key. Lists cannot be keys in the dictionary.
Modifying Values in a Dictionary
>>> alien['color'] = 'yellow'
>>> print(alien)
{'color': 'yellow', 'points': 5}
Removing Key-Value Pairs
>>> del alien['points']
>>> print(alien)
{'color': 'yellow'}
Merge two dictionaries
>>> dict1 = { "name":"owen", "age": 18 }
>>> dict2 = { "birthday": "1999-11-22"}
>>> x = dict1|dict2
>>> print(x)
{'name': 'owen', 'age': 18, 'birthday': '1999-11-22'}
>>> a = { 'x' : 1 , 'y' : 2 }
>>> b = { 'y' : 3 , 'z' : 4 }
>>> c = a|b
>>> print(c)
{'x': 1, 'y': 3, 'z': 4}
The in operator works on dictionaries. (keys) To see whether something appears as a value in a dictionary, you can use the method .values().
>>> x = {'one': 'apple', 'two': 'banana', 'three': 'orange'}
>>> 'one' in x
True
>>> 'uno' in x
False
>>>'orange' in x.values()
True
>>> stuff = {}
>>> dir(stuff)
['__class__', '__class_getitem__', '__contains__', '__delattr__', '__delitem__',
'__dir__', '__doc__', '__eq__', '__format__', '__ge__', '__getattribute__',
'__getitem__', '__gt__', '__hash__', '__init__', '__init_subclass__', '__ior__',
'__iter__', '__le__', '__len__', '__lt__', '__ne__', '__new__', '__or__',
'__reduce__', '__reduce_ex__', '__repr__', '__reversed__', '__ror__', '__setattr__',
'__setitem__', '__sizeof__', '__str__', '__subclasshook__', 'clear', 'copy',
'fromkeys', 'get', 'items', 'keys', 'pop', 'popitem', 'setdefault', 'update','values']
>>> help(dict.get)
Help on method_descriptor:
get(self, key, default=None, /)
Return the value for key if key is in the dictionary, else default.
>>> counts = { 'chuck' : 1 , 'annie' : 42, 'jan': 100}
>>> print(counts.get('jan', 0)) #0 is the default value
100
>>> print(counts.get('anni', 1550))
1550
word = 'banana'
d = {}
word_list = list('banana')
for c in word_list:
d[c] = d.get(c,0) + 1
print(d)
{'b': 1, 'a': 3, 'n': 2}
# Looping Through All Key-Value Pairs
favorite = {
'jen': 'python',
'sarah': 'c',
'edward': 'ruby',
}
for x, y in favorite.items():
print(x, y)
jen python
sarah c
edward ruby
# Looping Through All Values
for y in favorite.values():
print(y)
python
c
ruby
# Looping Through All the Keys in a Dictionary
for x in favorite.keys():
print(x)
jen
sarah
edward
You can nest a set of dictionaries inside a list, a list of items inside a dictionary, or even a dictionary inside another dictionary. A list or a dictionary cannot be the key (The key should be immutable).
Dictionaries in a list
alien_0 = {'color': 'green', 'points': 5}
alien_1 = {'color': 'yellow', 'points': 10}
alien_2 = {'color': 'red', 'points': 15}
aliens = [alien_0, alien_1, alien_2]
A List in a Dictionary
pizza = {
'crust': 'thick',
'toppings': ['mushrooms', 'extra cheese'],
}
print(pizza['crust'], pizza['toppings'][1])
thick extra cheese
A Dictionary in a Dictionary
users = {
'aeinstein': {
'first': 'albert',
'last': 'einstein',
'location': 'princeton',
},
'mcurie': {
'first': 'marie',
'last': 'curie',
'location': 'paris',
},
}
full_name = users['aeinstein']['first']+" "+users['aeinstein']['last']
location = users['aeinstein']['location']
print("Full name: " + full_name)
print("Location: " + location)
Full name: Albert Einstein
Location: Princeton
Elements are key-value pairs. Empty dictionary {}
Features:unpredictable order, key-value pairs are mutable (keys are immutable, but you can modify values). Do not make repeated keys.
.get() (value or default value)
Looping: .items(), .keys(), .values()
in operator works on keys (but you can use .values())
Nesting: A list of dictionaries, a list in a dictionary, a dictionary in a dictionary
print("简易记账本(九月)")
Sept=[]
for date in range(31):
# Sept.append([])
Sept.append({})
while True:
day=int(input("请问输入几号的开销?结束请输入0:"))
if day==0:
break
else:
print("请输入每一笔开销,结束请输入0:")
n=1
while True:
each = float(input("第"+str(n)+"笔:"))
if each == 0:
break
else:
# Sept[day-1].append(each)
y = input("请选择: a.衣 b.食 c.住 d.行 e.其他")
Sept[day-1][y]=Sept[day-1].get(y,0)+each
n = n + 1
print("记录成功")
total=0
for each_day in Sept:
if each_day:
# total = total + sum(each_day)
total = total + sum(each_day.values())
print("本月支出汇总报告")
print("总支出:" + str(total))
sub = {}
items = ['a', 'b', 'c', 'd', 'e']
for each_day in Sept:
for z in items:
sub[z] = each_day.get(z,0)+sub.get(z,0)
print("衣:", sub['a'])
print("食:", sub['b'])
print("住:", sub['c'])
print("行:", sub['d'])
print("其他:", sub['e'])
A tuple is a sequence of values much like a list. The important difference is that tuples are immutable
The empty tuple can be written as tuple().
>>> t = () #Empty is False
>>> print(t)
()
>>> t = ('a', 'b', 'c', 'd', 'e')
To create a tuple with a single element, you have to include the final comma:
>>> t1 = ('a',)
>>> type(t1)
tuple
>>> t2 = ('a')
>>> type(t2)
str
Most list operators also work on tuples.
>>> t = ('a', 'b', 'c', 'd', 'e')
>>> print(t[0])
'a'
>>> print(t[1:3])
('b', 'c')
Tuple is immutable. You can't modify the elements of a tuple, but you can replace one tuple with another:
>>> t[0] = 'A'
TypeError: object doesn't support item assignment
>>> t = ('A',) + t[1:]
>>> print(t)
('A', 'b', 'c', 'd', 'e')
If you want to modify a tuple, you can convert it to a list, and then convert it back.
>>> t = ('a', 'b', 'c', 'd', 'e')
>>> s = list(t)
>>> s[0] = 'A'
>>> t = tuple(s)
Comparing and sorting (the same for lists)
>>> (0, 1, 2) < (0, 3, 4)
True
>>> (0, 1, 2000000) < (0, 3, 4)
True
>>> t = [(2, 4), (0, 1, 2), (0, 3, 4)]
>>> t.sort()
>>> print(t)
[(0, 1, 2), (0, 3, 4), (2, 4)]
in operator (the same for lists)
>>> t = ('a', 'b', 'c', 'd', 'e')
>>> print('a' in t)
True
Multiple Assignment (the same for lists)
>>> m = ('have', 'fun')
>>> x, y = m
>>> x
'have'
>>> y
'fun'
>>> x, y = y, x #swap
Iteration with multiple values (the same for lists in lists, tuples in lists, lists in tuples)
t = [('a',1), ('b',2), ('c',3)]
# t = (('a',1), ('b',2), ('c',3))
# t = [['a',1], ['b',2], ['c',3]]
for x, y in t:
print(x)
print(y)
>>> d = {'a':10, 'b':1, 'c':22}
>>> t = list(d.items())
>>> t
[('b', 1), ('a', 10), ('c', 22)]
Using tuples as keys in dictionaries
>>> directory = dict()
>>> directory[('Taylor', 'Swift')] = 100
>>> print(directory)
{('Taylor', 'Swift'): 100}
The element can be any type. The empty is ().
Features: Ordered, Immutable, Repeatable
Index and slice are the same with that of lists.
You cannot modify the elements of a tuple, but you can replace one tuple with another.
Comparing, multiple assignment, in operator
Tuples can be keys of a dictionary.
container | Feature | |
---|---|---|
List | [] | ordered; mutable; repeatable |
Tuple | () | ordered; immutable; repeatable |
Dictionary | {} | not ordered; key-value pairs and values are mutable, keys are not; values are repeatable, keys are not |
Values are immutable. Thus, numbers, strings, tuples are immutable. Lists, dictionaries are mutable.
What does it mean for immutable or mutable? Assignment, Modification, Reference
1. what is assignment? variable $\rightarrow$ computer memory $\rightarrow$ object
2. Modification
>>> x = "abc"
>>> x = "def"
a. make a new assignment
>>> x = [1,2,3]
>>> x = [4,5,6]
b. make a modification by methods for lists. You do not change the address.
>>> x = [1,2,3]
>>> del x[2]
>>> del x[1]
>>> del x[0]
>>> x.append(4)
>>> x.append(5)
>>> x.append(6)
3. Reference
>>> x = "abc"
>>> y = x
>>> x = "def"
>>> print(y)
"abc"
>>> x = [1,2,3]
>>> y = x
>>> del x[2]
>>> x.append(4)
>>> print(y)
[1,2,4]
>>> x = [1,2,3]
>>> y = x[:]
>>> del x[2]
>>> x.append(4)
>>> print(y)
[1,2,3]